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6.6x^2=4.1x
We move all terms to the left:
6.6x^2-(4.1x)=0
We add all the numbers together, and all the variables
6.6x^2-(+4.1x)=0
We get rid of parentheses
6.6x^2-4.1x=0
a = 6.6; b = -4.1; c = 0;
Δ = b2-4ac
Δ = -4.12-4·6.6·0
Δ = 16.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.1)-\sqrt{16.81}}{2*6.6}=\frac{4.1-\sqrt{16.81}}{13.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.1)+\sqrt{16.81}}{2*6.6}=\frac{4.1+\sqrt{16.81}}{13.2} $
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